Volume adjustments - 2^(x/6) vs 10^(x/20)?

[Amether]

If I sneak a look at some JS plugins, they tend to use the formula 2^(x/6) to convert a slider that gives an dB adjustment of x to a multiplier for each sample.

Why is this used and not 10^(x/20)?

As I understand it, this 10^(x/20) is more 'correct'? (source: http://www.sengpielaudio.com/calculator-levelchange.htm)

I appreciate the values turn out very similar until you reach such huge changes in volume that it kinda doesn't matter, but y'know, still. What's the reasoning behind this? CPU?

[DarkStar]

>>> https://forum.cockos.com/showthread.php?t=221913

[schwa]

2^(x/6) is an approximation.

[Tale]

At some point 2^x might have been more efficient, in which case the approximation makes sense. However, nowadays 2^x and 10^x are just as (in)efficient. A slightly more efficient aproach would be exp(x*y), where y = log(10)/20.

[Amether]

Thanks all - I did search but clearly need better search skillz... sigh. I choose... inefficient!