Old 03-07-2021, 03:48 PM   #1
mabian
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Default Question on new Channel Mapper JSFX

Hello,

I am trying to use the new Channel Mapper plugin to switch the master track between channel pairs (1/2 or 3/4).

While doing so I found something I'm not sure I understand: shouldn't the attached settings merge input pairs 1/2 + 3/4 to output 1/2?
Here I just get channels 3/4 routed to output 1/2, is it expected?

Thanks,
Mario
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Old 03-08-2021, 04:59 AM   #2
schwa
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This mapping should result in:

in 1 => nowhere
in 2 => nowhere
in 3 => out 1
in 4 => out 2
in 3 => out 3
in 4 => out 4

Nothing is mapped to outs 3 and 4, and "unmapped outs pass through" is enabled, so the inputs pass through for those outputs. This is the same result you would get by default for any FX (not just the channel mapper JSFX) with this output pin mapping, because "unmapped outs pass through" is the default behavior.
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Old 03-08-2021, 06:07 AM   #3
mabian
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Ok, got it thanks!

This is indeed what I'm getting, I didn't pay enough attention to that "unmapped OUTPUT" name.

- Mario
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