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Old 12-31-2019, 02:21 PM   #7
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Join Date: May 2010
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Originally Posted by ashcat_lt View Post
If you want more technically accurate, you'd use 10^(-18/20)
Sorry, can I ask for some clarification? I expected that this formula would produce approx 8 as per your previous code sample, but it produces 0.125893.
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